我有一个数组:
myArray = [{'id':'73','foo':'bar'},{'id':'45','foo':'bar'}, etc.]
我无法更改数组的结构。我正在传递ID为45
,我想获取'bar'
数组中的该对象。
如何在JavaScript或jQuery中做到这一点?
我有一个数组:
myArray = [{'id':'73','foo':'bar'},{'id':'45','foo':'bar'}, etc.]
我无法更改数组的结构。我正在传递ID为45
,我想获取'bar'
数组中的该对象。
如何在JavaScript或jQuery中做到这一点?
Shortest,
var theAnswerObj = _.findWhere(array, {id : 42});
Consider "axesOptions" to be array of objects with an object format being {:field_type => 2, :fields => [1,3,4]}
function getFieldOptions(axesOptions,choice){
var fields=[]
axesOptions.each(function(item){
if(item.field_type == choice)
fields= hashToArray(item.fields)
});
return fields;
}
We can use Jquery methods $.each()/$.grep()
var data= [];
$.each(array,function(i){if(n !== 5 && i > 4){data.push(item)}}
or
var data = $.grep(array, function( n, i ) {
return ( n !== 5 && i > 4 );
});
use ES6 syntax:
Array.find, Array.filter, Array.forEach, Array.map
Or use Lodash https://lodash.com/docs/4.17.10#filter, Underscore https://underscorejs.org/#filter
I really liked the answer provided by Aaron Digulla but needed to keep my array of objects so I could iterate through it later. So I modified it to
var indexer = {};
for (var i = 0; i < array.length; i++) {
indexer[array[i].id] = parseInt(i);
}
//Then you can access object properties in your array using
array[indexer[id]].property
Use Array.prototype.filter()
function.
DEMO: https://jsfiddle.net/sumitridhal/r0cz0w5o/4/
JSON
var jsonObj =[
{
"name": "Me",
"info": {
"age": "15",
"favColor": "Green",
"pets": true
}
},
{
"name": "Alex",
"info": {
"age": "16",
"favColor": "orange",
"pets": false
}
},
{
"name": "Kyle",
"info": {
"age": "15",
"favColor": "Blue",
"pets": false
}
}
];
FILTER
var getPerson = function(name){
return jsonObj.filter(function(obj) {
return obj.name === name;
});
}
You can do this even in pure JavaScript by using the in built "filter" function for arrays:
Array.prototype.filterObjects = function(key, value) {
return this.filter(function(x) { return x[key] === value; })
}
So now simply pass "id" in place of key
and "45" in place of value
, and you will get the full object matching an id of 45. So that would be,
myArr.filterObjects("id", "45");
As long as the browser supports ECMA-262, 5th edition (December 2009), this should work, almost one-liner:
var bFound = myArray.some(function (obj) {
return obj.id === 45;
});
Building on the accepted answer:
jQuery:
var foo = $.grep(myArray, function(e){ return e.id === foo_id})
myArray.pop(foo)
Or CoffeeScript:
foo = $.grep myArray, (e) -> e.id == foo_id
myArray.pop foo
If you do this multiple times, you may set up a Map (ES6):
const map = new Map( myArray.map(el => [el.id, el]) );
Then you can simply do:
map.get(27).foo
You may try out Sugarjs from http://sugarjs.com/.
It has a very sweet method on Arrays, .find
. So you can find an element like this:
array.find( {id: 75} );
You may also pass an object with more properties to it to add another "where-clause".
Note that Sugarjs extends native objects, and some people consider this very evil...
You can use filters,
function getById(id, myArray) {
return myArray.filter(function(obj) {
if(obj.id == id) {
return obj
}
})[0]
}
get_my_obj = getById(73, myArray);
myArray.filter(function(a){ return a.id == some_id_you_want })[0]
由于您已经在使用jQuery,因此可以使用旨在搜索数组的grep函数:
var result = $.grep(myArray, function(e){ return e.id == id; });
结果是包含找到的项目的数组。如果您知道对象始终存在并且只发生一次,则可以使用result[0].foo
获取值。否则,您应该检查结果数组的长度。例:
if (result.length === 0) {
// no result found
} else if (result.length === 1) {
// property found, access the foo property using result[0].foo
} else {
// multiple items found
}
This solution may helpful as well:
I made it just like
$.grep
and if one object is find out, function will return the object, rather than an array.